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Question

Find : sin2xcos2xsin x cos xdx

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Solution

sin2xcos2xsin x cos xdx

= cos2xsin2xsinx cosxdx

= 2cos2x2sinx cosxdx

=2cos2xsin2x dx

=-2cot2x dx

=2log|sin2x|2+C=-log|sin2x|+C=log|cosec 2x|+C

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