Find $e / m$ for ${H e}^{2 +}$ ion.

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Solution

Charge on $H e^{+ 2} \Rightarrow 2 \times 1.6 \times 10^{- 19} C$
mass of ${H e}^{+ 2}$ =mass of $2$ proton+mass of $2$ neutrons
$= 4 \times 1.67 \times 10^{- 27} k g = 6.68 \times 10^{- 27} k g \frac{e}{m} = \frac{3.2 \times 10^{- 19}}{6.68 \times 10^{- 27}} = 0.48 \times 10^{8} = 4.8 \times 10^{7}$

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