Find each of the following products:
(i) (−4)×(−5)×(−8)×(−10)
(ii) (−6)×(−5)×(−7)×(−2)×(−3)
(iii) (−60)×(−10)×(−5)×(−1)
(iv) (−30)×(−20)×(−5)
(v) (−3)×(−3)×(−3)×..6 times
(vi) (−5)×(−5)×(−5)×...5 times
(vii) (−1)×(−1)×(−1)×...200 times
(viii) (−1)×(−1)×(−1)×...171 times
(i) (−4)×(−5)×(−8)×(−10)
Since the number of negative integers in the product is even, the product will be positive.
⇒(−4)×(−5)×(−8)×(−10)=1600
(ii) (−6)×(−5)×(−7)×(−2)×(−3)
Since the number of negative integers in the product is odd, the product will be negative.
⇒(−6)×(−5)×(−7)×(−2)×(−3)=−1260
(iii) (−60)×(−10)×(−5)×(−1)
Since the number of negative integers in the product is even, the product will be positive.
⇒(−60)×(−10)×(−5)×(−1)=3000
(iv) (−30)×(−20)×(−5)
Since the number of negative integers in the product is odd, the product will be negative.
⇒(−30)×(−20)×(−5)=3000
(v) (−3)×(−3)×(−3)×..6 times
Since the number of negative integers in the product is even, the product will be positive.
⇒(−3)×(−3)×(−3)×..6 times =36=729
(vi) (−5)×(−5)×(−5)×...5 times
Since the number of negative integers in the product is odd, the product will be negative.
⇒(−5)×(−5)×(−5)×...5 times =55=−3125
(vii) (−1)×(−1)×(−1)×...200 times
Since the number of negative integers in the product is even, the product will be positive.
⇒(−1)×(−1)×(−1)×...200 times =(−1)200
(viii) (−1)×(−1)×(−1)×...171 times
Since the number of negative integers in the product is odd, the product will be negative.
⇒(−1)×(−1)×(−1)×...171 times =(−1)171=−1