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Question

Find each of the following products:
(i) (4)×(5)×(8)×(10)
(ii) (6)×(5)×(7)×(2)×(3)
(iii) (60)×(10)×(5)×(1)
(iv) (30)×(20)×(5)
(v) (3)×(3)×(3)×..6 times
(vi) (5)×(5)×(5)×...5 times
(vii) (1)×(1)×(1)×...200 times
(viii) (1)×(1)×(1)×...171 times

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Solution

(i) (4)×(5)×(8)×(10)

Since the number of negative integers in the product is even, the product will be positive.
(4)×(5)×(8)×(10)=1600
(ii) (6)×(5)×(7)×(2)×(3)

Since the number of negative integers in the product is odd, the product will be negative.

(6)×(5)×(7)×(2)×(3)=1260

(iii) (60)×(10)×(5)×(1)

Since the number of negative integers in the product is even, the product will be positive.

(60)×(10)×(5)×(1)=3000
(iv) (30)×(20)×(5)

Since the number of negative integers in the product is odd, the product will be negative.

(30)×(20)×(5)=3000

(v) (3)×(3)×(3)×..6 times

Since the number of negative integers in the product is even, the product will be positive.
(3)×(3)×(3)×..6 times =36=729

(vi) (5)×(5)×(5)×...5 times

Since the number of negative integers in the product is odd, the product will be negative.

(5)×(5)×(5)×...5 times =55=3125

(vii) (1)×(1)×(1)×...200 times

Since the number of negative integers in the product is even, the product will be positive.

(1)×(1)×(1)×...200 times =(1)200

(viii) (1)×(1)×(1)×...171 times

Since the number of negative integers in the product is odd, the product will be negative.
(1)×(1)×(1)×...171 times =(1)171=1


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