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Question

Find x, y, a and b if 3x+4y2x-2ya+b2a-b-1=2 2 45-5-1

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Solution

Since the corresponding elements of two equal matrices are equal,

3x+4y2x-2ya+b2a-b-1=2245-5-13x+4y=2 ...1 x-2y=4x=4+2y ...2 Putting the value of x in eq. 1, we get 34+2y+4y=2 12+6y+4y=2 12+10y=2 10y=2-1210y=-10 y=-1010=-1Putting the value of y in eq. 2, we get x=4+2-1 x=4-2=2a+b=5 a=5-b ...32a-b=-5 ...4 Putting the value a in eq. 4, we get 25-b-b=-510-2b-b=-510-3b=-5-3b=-15 b=-15-3 b=5Putting the value of b in eq. 3, we get a=5-5a=0

x=2 , y=-1 , a=0 and b=5

[3x+4ya+b22abx2y1]=[25 25 41]
[3x+4ya+b22abx2y1]=[25 25 41]

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