Find empirical formula of 4g calcium , 6.022 × 10^{23} atoms carbon, 4.8 g oxygen

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which has more weight 6.022*1023 atoms of oxygen or carbon?

Q. 12 g C-12 contains

6.022 \times 10^{23}

atoms of carbon.
(a)

6.022 \times 10^{23}

is known as .............
(b) Calculate the number of carbon atoms present in 48 g C-12.
(c) Which weighs more,

6.022 \times 10^{23}

molecules of

C O_{2}

6.022 \times 10^{23}

molecules of

H_{2} O

1

g of

^{12} C

contains

6.022 \times 10^{23}

atoms of Carbon.

A hydrocarbon contains 4.8 g of carbon per gram of hydrogen.
Calculate:
(a) the gram atom of each,
(b) find the empirical formula,
(c) find molecular formula, if its vapour density is 29.

Q. Assertion :Both

138

g of

K_{2} C O_{3}

and

12

g of carbon have same number of carbon atoms. Reason: Both contain

1

g atom of carbon which contains

6.022 \times 10^{23}

carbon atoms.

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