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Byju's Answer
Standard IX
Physics
Binding Energy
find energy r...
Question
find energy released when two
1
H
2
nuclei fuse to form one
2
He
4
nucleus. BEN of H and He are 1.1 MeV and 7 MeV respectively.
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Solution
S
i
n
c
e
t
h
e
b
i
n
d
i
n
g
e
n
e
r
g
y
p
e
r
n
u
c
l
e
o
n
i
s
g
i
v
e
n
h
e
n
c
e
B
i
n
d
i
n
g
e
n
e
r
g
y
o
f
t
h
e
2
H
e
4
=
4
×
7
M
e
V
=
28
M
e
V
B
i
n
d
i
n
g
e
n
e
r
g
y
o
f
t
h
e
1
H
2
=
2
×
1
.
1
M
e
V
=
2
.
2
M
e
V
s
o
∆
E
=
2
m
a
s
s
o
f
1
H
2
-
m
a
s
s
o
f
2
H
e
4
∆
E
=
2
M
p
+
M
n
-
2
.
2
-
2
M
p
+
2
M
n
-
28
∆
E
=
2
M
p
+
2
M
n
-
4
.
4
-
2
M
p
-
2
M
n
+
28
∆
E
=
23
.
6
M
e
V
Suggest Corrections
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Similar questions
Q.
The binding energies per nucleon for deuteron
(
1
H
2
)
and helium
(
2
H
e
4
)
are 1.1 MeV and 7.0 MeV, respectively. Calculate the energy released when two deuterons fuse to form a helium nucleus
(
2
H
e
4
)
Q.
The binding energies per nucleon for deutron
(
1
H
2
)
and helium
(
2
H
e
4
)
are
1.1
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7.0
MeV respectively. Calculate the energy released, when two deutrons fuse to form a helium nucleus
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2
H
e
4
)
.
Q.
The binding energy per nucleon of deuteron
(
1
H
2
)
and helium nucleus
(
2
H
e
4
)
is
1.1
M
e
V
and
7
M
e
V
respectively. If two deuteron nuclei reacts to form a single helium nucleus, then the energy released is
Q.
The binding energy/nucleon of deuteron
(
1
H
2
)
and the helium atom
(
2
H
e
4
)
are
1.1
MeV and
7
MeV respectively. If the two deuteron atoms fuse to form a single helium atom, then the energy released is.
Q.
The binding energy per nucleon in deuterium and helium nuclei are
1.1
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and
7.0
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V
, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is :
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