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Question

Find equation of a line which passes through point (2,3) and the point of intersection of the lines x+y+4=0 and 3xy8=0

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Solution

Given the equation of the lines,
x+y=4.....(1) and 3xy=8.....(2).
Solving (1) and (2) we get, x=1,y=5.
Now the equation of the line passing through the points (2,3) and (1,5) is,
y+35+3=x212
or, y+3=2(x2)
or, y2x=7.

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