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Area of a Triangle

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Question

Find equation of a line whose $x$ -intercept is $- 3$ and which is perpendicular to the line $3 x + 5 y - 8 = 0$ .

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Solution

Given $x$ intercept $= - 3$
point $= (- 3, 0)$
Since the line is perpendicular to $3 x + 5 y - 8 = 0$
Slope $= \frac{5}{3}$
Equation of line $y - 0 = \frac{5}{3} (x + 3)$
Thus, $3 y = 5 x + 15$ is the required equation of the line.

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