Find equation of angle bisector of plane $x + 2 y + 3 z - z = 0$ and $2 x - 3 y + z + 4 = 0$ .

Open in App

Solution

$\begin{matrix} E q u^{n} o f a n g l e b i sec t o r o f p l a n e a r e : \frac{x + 2 y + 3 z - 1}{\sqrt{1 + 4 + 9}} = \pm \frac{(2 x - 3 y + z + 4)}{\sqrt{4 + 9 + 1}} x + 2 y + 3 z - 1 = \pm (2 x - 3 y + z + 4) t a k i n g + v e s i g n : x + 2 y + 3 z - 1 = 2 x - 3 y + z + 4 x - 5 y - 2 z + 5 = 0 t a k i n g (- v e) s i g n 3 x - y + 4 z + 3 = 0 \end{matrix}$
which is the required answer.

Suggest Corrections

Similar questions

2 x - 3 y + z + 2 = 0

x + 2 y - 3 z + 1 = 0

x + 2 y + 3 z - 4 = 0 = 2 x + y - z + 5

5 x + 3 y - 6 z + 8 = 0

\frac{x - 1}{2} = \frac{y + 2}{- 3} = \frac{z}{5}

x - y + z + 2 = 0

2 x + 3 y - 3 z = 0 3 x - 3 y + z = 0 3 x - 2 y - 3 z = 0

5 x + 3 y + 6 z + 8 = 0

x + 2 y + 3 z - 4 = 0

2 x + y - z + 5 = 0

Join BYJU'S Learning Program