Find equation of circle whose certasian equation are $x = - 3 + 2 sin θ, y = 4 + 2 cos θ$ .

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Solution

$x + 3 = 2 sin θ, y - 4 = 2 cos θ$
$(x + 3)^{2} + (y - 4)^{2} = 4 {sin}^{2} θ + 4 {cos}^{θ}$
So, equation of circle is
$⟹ (x + 3)^{2} + (y - 4)^{2} = 4$

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