Find equation of the circle which touch the ordinate axes at a distance of unit $5$ from the origin.

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Solution

As the circle is given to touch the ordinate axes at a distance $5$ units for the origin. Then its centre is at $(5, 5)$ and radius being $5$ units.
Then the equation of the circle is
$(x - 5)^{2} + (y - 5)^{2} = 5^{2}$ .

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Find equation of the circle which touch the ordinate axes at a distance of unit 5 from the origin.

As the circle is given to touch the ordinate axes at a distance 5 units for the origin. Then its centre is at (5,5) and radius being 5 units.Then the equation of the circle is (x−5)2+(y−5)2=52.

Find equation of the circle which touch the ordinate axes at a distance of unit $5$ from the origin.

As the circle is given to touch the ordinate axes at a distance $5$ units for the origin. Then its centre is at $(5, 5)$ and radius being $5$ units.
Then the equation of the circle is
$(x - 5)^{2} + (y - 5)^{2} = 5^{2}$ .