Find equivalent and molar conductance of 0.01 M solution of $K_{2} S O_{4}$ whose specific conductance is 1.26 x $10^{- 3} Ω^{- 1} c m^{- 1}$

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Solution

Specific conductance = $1.26 \times 10^{- 3} Ω^{- 1} c m^{- 1}$
Molarity of solution $M = 0.01 M$
Molar conductance $\land_{m} = \frac{K}{C} = \frac{1.26 \times 10^{- 3}}{0.01 \times 10^{- 3}} m o l / c m^{3}$
$= 126$

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