Question

Find equivalent capacitance across $AB$ (all capacitances in $\mu F$)

Answer 1

Equivalent resistance $\frac{1}{C}=\frac{1}{36}+\frac{1}{5}+\frac{1}{12}$

$=\frac{5+36+15}{180}=\frac{56}{180}$

$C=3.21\mu F$