Question

Find equivalent capacitance between $A$ and $B$. [Assume each conducting plate is having same dimensions and neglect the thickness of the plate, $\frac{{ϵ}_{0}A}{d}=7\mu F$ where $A$ is area of plates, $A>>d$]

• A. $7\mu F$
• B. $11\mu F$
• C. $12\mu F$
• D. $14\mu F$

Answer 1

The correct option is B $11\mu F$


From the above figure,
$C_{eq}=C+\frac{C\times C/2}{C+C/2}=\frac{4C}{3}$

Now,

$C_{AB}=\frac{\frac{4C}{3}\times C}{\frac{7C}{3}}+C=\frac{11C}{7}=11\mu F$