Question

Find equivalent resistance between $A$ and $B$

• A. $\frac{4R}{5}$
  
• B. $\frac{2R}{3}$
  
• C. $\frac{2R}{5}$
  
• D. $\frac{3R}{2}$
  

Answer 1

The correct option is A $\frac{4R}{5}$


As evident from the diagram, the circuit resembles mirror symmetry about the line of symmetry. So, we can remove the connection at the point of symmetry and further reduce the circuit as shown below.

The circuit can be further reduced by using the series and parallel combination technique as shown below.


$\frac{1}{R_{e}q}=\frac{3}{8R}+\frac{1}{2R}+\frac{3}{8R}$

$\Rightarrow R_{eq}=\frac{4R}{5}$