Question

Find equivalent resistance of the circuit between the terminal $A$ and $B$.

• A. $\frac{4}{3}\Omega$
• B. $\frac{8}{3}\Omega$
• C. $\frac{16}{3}\Omega$
• D. $\frac{32}{3}\Omega$

Answer 1

The correct option is C $\frac{16}{3}\Omega$

The given circuit is wheat stone bridge and it is in balance condition.

$\because \frac{10}{5}=\frac{6}{3}$

Current through $20\Omega$ will not flow, so this can be discarded from the circuit.


Resistances $10\Omega$ and $6\Omega$ are in series and also $5\Omega$ and $3\Omega$ are in series.

Hence this is equivalent to

$R_{eq}=\frac{16\times 8}{16+8}=\frac{16}{3}\Omega$