CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Existence of Limit

Find f'-3 usi...

Question

Find f'(-3) using definition if $f (x) = \frac{2 x}{x - 3}$

Open in App

Solution

$\begin{matrix} f (- 3) = & \frac{2 \cdot (- 3)}{(- 3) - 3} = \frac{- 6}{- 6} = 1 \end{matrix}$

Suggest Corrections

thumbs-up

0

Similar questions

f (x) = e^{\sqrt{2 x + 3}}

f (11)

, by using the definition.

f (x)

[- 3, 2]

, then find the domain of definition of

f ([| x |])

f ([2 x + 3])

f (x)

[- 3, 3]

then find the domain of definition of

f (| 2 x + 3 |)

f (x) = (x + 1) (x + 2) (x + 3) . . . . . (x + n)

f^{'} (0)

.

Q. The domain of definition of

f (x) = \sqrt{x - 3 - 2 \sqrt{x - 4}} - \sqrt{x - 3 + 2 \sqrt{x - 4}}

is

(a) [4, ∞)
(b) (−∞, 4]
(c) (4, ∞)
(d) (−∞, 4)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Introduction to Limits

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Existence of Limit

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon