Question

Find $f\left(4\right)$ if $f\left(x\right)=x^2+\frac{1}{x^2}$

Answer 1

$f\left(x\right)=x^2+\frac{1}{x^2}f\left(4\right)=4^2+\frac{1}{4^2}f\left(4\right)=16+\frac{1}{16}=16.06$