Question

Find $f\left(2.01\right),$if $f\left(x\right)=4x^2+5x+2$

• A. 28.2102
• B. 28.2104
• C. 28.2105
• D. 28.2103

Answer 1

The correct option is B 28.2104

Given that,

$f\left(x\right)=4x^2+5x+2$

Put $x=2.01$ and we get,

$f\left(2.01\right)=4\times {\left(2.01\right)}^2+5\times 2.01+2$

$=4.0401\times 4+10.05+2$

$=16.1604+10.05+2$

$=28.2104$

Hence, this is the answer.