Find five different solutions of each of the following equations:
(i) 2x – 3y = 6
(ii) $\frac{2 x}{5} + \frac{3 y}{10} = 3$
(iii) 3y = 4x

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Solution

(i) 2x – 3y = 6

x 0 3 $-$ 3 $\frac{9}{2}$ 2

y $-$ 2 0 $-$ 4 1 $\frac{- 2}{3}$

(ii) $\frac{2 x}{5} + \frac{3 y}{10} = 3$

x 0 $\frac{15}{2}$ 5 10 3

y 10 0 $\frac{10}{3}$ $\frac{- 10}{3}$ 6

(iii) 3y = 4x

x 3 $-$ 3 $-$ 6 6 0

y 4 $-$ 4 $-$ 8 8 0

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Similar questions

Find five different solutions of each of the following equations:

(a) 2x - 3y = 6

(b) $\frac{2 x}{5} + \frac{3 y}{10} = 3$

Write two solutions of the form $x = 0, y = 1 a n d x = b, y = 0$ for each of the following equations:

(i) 5x - 2y = 10 (ii) - 4x + 3y = 12 (iii) 2x + 3y = 24

2 x - 3 y = 5

4 x - 6 y = 7

2 x - 3 y + 7 = 0

Find the value $k$ for which each of the following systems of equations has a unique solution:

$4 x - 5 y = k, 2 x - 3 y = 12.$

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