(a) x2−2x−3=(x−3)(x+1)=[x−(−1)](x−3)
a=−1 and b=3,a<b.
By §5 the above expression is +ive if x does not lie between a and b i.e. if x does not lie between −1 and 3. Again it will be −ive if x lies between a and b i.e. x lies between −1 and 3.
(b) +ive if x does not lie between −3 and 12.
(c) Ans.(b). x2+2ax+10−3a=+ive∀ real values of x if disc 4a2−4(10−3a)=−ive and sign of the first term i.e., 1 is +ive.
∴ a2+3a−10<0
or (a+5)(a−2)<0 ∴ −5<a<2