Question

Find four rational numbers equivalent to the following.
$\frac{7}{-15}$

Answer 1

$\frac{7}{-15}$ can also be written as $\frac{(7\times (-1\left)\right)}{-15\times (-1))}=\frac{-7}{15}$

To find equivalent rational number, we have to multiply and divide numerator with same number except $0$

$\therefore \frac{-7}{15}=\frac{-7\times 2}{15\times 2}=\frac{-14}{30}$

$\therefore \frac{-7}{15}=\frac{-7\times 3}{15\times 3}=\frac{-21}{45}$

$\therefore \frac{-7}{15}=\frac{-7\times 4}{15\times 4}=\frac{-28}{60}$

$\therefore \frac{-7}{15}=\frac{-7\times 5}{15\times 5}=\frac{-35}{75}$

So, equivalent numbers of $\frac{-7}{15}$ are$\frac{-14}{30},$ $\frac{-21}{45},\frac{-28}{60},\frac{-35}{75}$

Multiplying and dividing numbers by $-1$ we get,

Equivalent numbers as $\frac{14}{-30},$ $\frac{21}{-45},\frac{28}{-60},\frac{35}{-75}$