Find- cos70-sin20-cos59-sin31-8 sin230- -

The correct option is B 0cos70^∘/sin20^∘+cos59^∘/sin31^∘ 8 sin^2 30^∘ ⇒sin20^∘/sin20^∘ + nbsp;sin31^∘/sin31^∘ 8(1/2)^2 (∵ cosθ = sin(90^∘ θ), sin30^∘ = ...

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Byju's Answer

Standard X

Mathematics

Complementary Trigonometric Ratios

Find: cos70∘/...

Question

Find:
$\frac{c o s 70^{\circ}}{s i n 20^{\circ}} + \frac{c o s 59^{\circ}}{s i n 31^{\circ}} - 8 s i n^{2} 30^{\circ} =$ ______.

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Solution

The correct option is C 0.0
$\frac{c o s 70^{\circ}}{s i n 20^{\circ}} + \frac{c o s 59^{\circ}}{s i n 31^{\circ}} - 8 s i n^{2} 30^{\circ} \Rightarrow \frac{s i n 20^{\circ}}{s i n 20^{\circ}} + \frac{s i n 31^{\circ}}{s i n 31^{\circ}} - 8 (\frac{1}{2})^{2} (∵ c o s θ = s i n (90^{\circ} - θ), s i n 30^{\circ} = (\frac{1}{2}) \Rightarrow 1 + 1 - 8 \times \frac{1}{4} \Rightarrow 2 - 2 = 0$

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Similar questions

Q. Evaluate

\frac{c o s 70^{\circ}}{s i n 20^{\circ}} + \frac{c o s 59^{\circ}}{s i n 31^{\circ}} - 8 s i n^{2} 30^{\circ} = 0

\frac{c o s 70^{\circ}}{s i n 20^{\circ}} + \frac{c o s 59^{\circ}}{s i n 31^{\circ}} - 8 s i n^{2} 30^{\circ}

is equal to

Q. Find the value of the following expression.

\frac{c o s 70^{\circ}}{s i n 20^{\circ}} + \frac{c o s 59^{\circ}}{s i n 31^{\circ}} - 8 s i n^{2} 30^{\circ}

$\frac{c o s 70^{\circ}}{s i n 20^{\circ}} + \frac{c o s 59^{\circ}}{s i n 31^{\circ}} - 8 s i n^{2} 30^{\circ} =$

Q. Find the value of:

\frac{cos 70^{\circ}}{sin 20^{\circ}} + \frac{cos 59^{\circ}}{sin 31^{\circ}} + \frac{cos θ}{sin (90 - θ)} - 8 {cos}^{2} 60^{\circ}

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Find: cos70∘sin20∘+cos59∘sin31∘−8sin230∘= ______.

The correct option is C 0.0cos70∘sin20∘+cos59∘sin31∘−8sin230∘⇒sin20∘sin20∘+sin31∘sin31∘−8(12)2(∵ cosθ=sin(90∘−θ), sin30∘=(12)⇒1+1−8×14⇒2−2=0

Find:
$\frac{c o s 70^{\circ}}{s i n 20^{\circ}} + \frac{c o s 59^{\circ}}{s i n 31^{\circ}} - 8 s i n^{2} 30^{\circ} =$ ______.