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Question

Find ddx(2cos2x)

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Solution

Let y=2cos2x
log y=log(2cos2x)=cos2x.log 2

On diffrentiating w.r.t x, we get
1y.dydx=log 2.ddx(cos x)21y.dydx=log2.[2cos x].ddx(cos x)=log 2. 2.cos x.(sin x)=log 2. (sin2 x) dydx=y.(sin 2x) log 2


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