Find d y-d x for y-log a x-log x a-log x x-log a a

Y=log_a x+log_x a+log_x x+log_a a =log x/log a+log a/log x+1+log a/log a dy/dx=1/log a1/x+log a( 1/(log x^2) )1/x+0+0 =1/xlog a log a/x(log x)^2 ...

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Arithmetic Progression

Find d y/d x ...

Question

Find $\frac{d y}{d x}$ for $y = l o g_{a} x + l o g_{x} a + l o g_{x} x + l o g_{a} a$

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Similar questions

y = l o g_{a} x + l o g_{x} a + l o g_{x} x + l o g_{a} a

\frac{d y}{d x} =

y + l o g_{a} x + l o g_{x} a + l o g_{a} a

\frac{d y}{d x} =

y = l o g x^{x}

\frac{d y}{d x}

Y = log x^{x}

\frac{d y}{d x}

y = (log x)^{x} + x^{log x}

\frac{d y}{d x}

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