Question

Find $\frac{dy}{dx}$in the following questions:

2x+3y=sin x.

Answer 1

Given, 2x+3y= sin x

Differentiating both sides w.r.t. x, we get

$\frac{d}{dx}(2x+3y)=\frac{d}{dx}\left(sinx\right)$

$2+3\frac{dy}{dx}=cosx\Rightarrow 3\frac{dy}{dx}=cosx-2\Rightarrow \frac{dy}{dx}=\frac{cosx-2}{3}$