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Question

Find dydxin the following questions:

2x+3y=sin y.

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Solution

Given, 2x+3y= sin y

Differentiating both sides w.r.t. x, we get

ddx(2x+3y)=ddx(siny)

2+3dydx=cos ydydx3dydxcos ydydx=2

(3cos y)dydx=2dydx=2cos y3


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