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Question

Find dydxin the following questions:

ax+by2=cos y

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Solution

Given, ax+by2=cos y

Differentiating both sides w.r.t. x, we get

ddx(ax+by2)=ddx(cos y)

a+2bydydx=sin ydydx2bydydx+sin ydydx=a

dydx(2by+sin y)=adydx=a2by+sin y


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