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Question

Find G.C.D of: (x29)(x3) and x2+6x+9

A
(x+3)2
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B
(x-3)
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C
(x+3)
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D
None of these
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Solution

The correct option is C (x+3)
p(x)=(x29)(x3)
=(x232)(x3)
=(x3)(x+3)(x3)
and
q(x)=x2+6x+9
=x2+3x+3x+9
=x(x+3)+3(x+3)
=(x+3)(x+3)
G.C.D of p(x) and q(x)=x+3
Option C is correct.

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