Find G.C.D of : $(x - 4)^{2} (x - 3)^{3}$ and $(x - 1) (x + 4) (x - 3)^{2}$

(x - 3)^{3}

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(x - 3)^{2}

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(x - 4)^{2} (x - 3)^{2}

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None of these

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Solution

The correct option is A $(x - 3)^{2}$
$(x - 4)^{2} (x - 3)^{3} = (x - 4) \times (x - 4) \times (x - 3) \times (x - 3) \times (x - 3)$
and
$(x - 1) (x + 4) (x - 3)^{2} = (x - 1) \times (x + 4) \times (x - 3) \times (x - 3)$
$∴$ G.C.D. $= (x - 3)^{2}$
Option D is correct.

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