Find general solution of sinx = tanx.

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Solution

$sin x = tan x$

$sin x = \frac{sin x}{cos x}$

$sin x (cos x - 1) = 0$

$f o r sin x = 0$

$x = n π,$

$f o r cos x = 1$

$cos x = cos 0$

$Q = 2 n π \pm 0$

$Q = 2 n π, n \leftarrow z$

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