Find general solution of the following equations:
$sin θ = \frac{1}{2}$ ?

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Solution

$sin θ = \frac{1}{2} sin θ = sin \frac{π}{6} θ = 2 n π + (- 1)^{n} \frac{π}{6}$

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Find general solution of the following equations:sinθ=12 ?

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Find general solution of the following equations:
$sin θ = \frac{1}{2}$ ?

$sin θ = \frac{1}{2} sin θ = sin \frac{π}{6} θ = 2 n π + (- 1)^{n} \frac{π}{6}$