Question

Find H.C.F. of $210,287$ and $301$ by division method.

Answer 1

Step 1: Find H.C.F. of first two numbers $210,287$ by division method

$$\begin{gathered} 210287(1 \\ \underline{-210} \\ 77210(2 \\ \underline{-154} \\ 5677(1 \\ \underline{-56} \\ 2156(2 \\ \underline{-42} \\ 1421(1 \\ \underline{-14} \\ 714(2 \\ \underline{-14} \\ 0 \end{gathered}$$

H.C.F of $210,287=7$

Step 2: Find H.C.F. of $7$ and $301$

$$\begin{gathered} 7301(43 \\ \underline{-301} \\ 00 \end{gathered}$$

The last divisor is the required H.C.F.

Hence, H.C.F. of $210,287$ and $301$ $=7$.