Question

find HCF of 39 and 65 by division method

Answer 1

$$\begin{gathered} 39)\overline{65}(1 \\ \underline{39} \\ 26)\overline{39(}1 \\ 13)\overline{26(}2 \\ \underline{26} \\ 0 \\ \mathrm{Since}\mathrm{the}\mathrm{last}\mathrm{divsor}\mathrm{is}13,\mathrm{so}\mathrm{HCF}\mathrm{of}39\mathrm{and}65=13 \end{gathered}$$