Find HCF of $54, 81$ and $99$ .

8

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9

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10

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11

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Solution

The correct option is A $9$
Factorization of the following.
$54 = 2 \times 3 \times 3 \times 3$
$81 = 3 \times 3 \times 3 \times 3$
$99 = 3 \times 3 \times 11$
Since, the common factor is $3 \times 3$ ,this implies that
$H . C . F = 3 \times 3$
Hence,the correct option $B$ .

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\frac{\frac{1}{\sqrt{9}} - \frac{1}{\sqrt{11}}}{\frac{1}{\sqrt{9}} + \frac{1}{\sqrt{11}}} \times \frac{10 + \sqrt{99}}{x} = \frac{1}{2}

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10 $^{9}$ , 8 $^{11}$ , 9 $^{10}$ , 7 $^{12}$ , ?

10, 20, 10, 9, 21, 11, 8, 22, 12, . . . . .

(10)^{9} + 2 (11)^{1} (10)^{8} + 3 (11)^{2} (10)^{7} + . . . + 10 (11)^{9} = k (10)^{9}

k

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