Find HCF of the numbers given.
$k, 2 k, 3 k, 4 k$ and $5 k$ , where k is any positive integer.

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Solution

Given number are K, 2K, 3K, 4K & 5K
where K is any positive integer.
Now $K = K$
$2 K = 2 \times K$
$3 K = 3 \times K$
$4 K = 2 \times 2 \times K$
$5 K = 5 \times K$
In all these numbers highest common factor is K.
Hence HCF of all given number is K.

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Good evening,

My doubt is

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