Question

Find he equation of the line passing through $(1,2,3)$ and perpendicular to the two lines $\frac{x}{1}=\frac{y}{2}=\frac{z}{-1}$ and $\frac{x-1}{3}=\frac{y}{2}=\frac{z}{6}$

Answer 1

Final equation will be :-

$\frac{x-1}{14}=\frac{y-2}{-9}=\frac{z-3}{-4}$