Find he products of the following expression (i) (4x+3y)(16x2−12xy+9y2) (ii) (5x−2y)(25x2+10xy+4y2)
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Solution
(i) (4x+3y)(16x2−12xy+9y2) =(4x+3y)[(4x)2−(4x)×(3y)+(3y)2] =(a+b)(a2−ab+b2) [Where a = 4x, b = 3y] =a3+b3=(4x)3+(3y)3=64x3+27y3 (ii) (5x−2y)(25x2+10xy+4y2) =(5x−2y)[(5x)2+(5x)×(2y)+(2y)2] =(a−b)(a2+ab+b2) [Where a = 5x, b = 2y] =a3−b3=(5x)3−(2y)3=125x3−8y3