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Question

Find he products of the following expression
(i) (4x+3y)(16x212xy+9y2)
(ii) (5x2y)(25x2+10xy+4y2)

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Solution

(i) (4x+3y)(16x212xy+9y2)
=(4x+3y)[(4x)2(4x)×(3y)+(3y)2]
=(a+b)(a2ab+b2) [Where a = 4x, b = 3y]
=a3+b3=(4x)3+(3y)3=64x3+27y3
(ii) (5x2y)(25x2+10xy+4y2)
=(5x2y)[(5x)2+(5x)×(2y)+(2y)2]
=(ab)(a2+ab+b2) [Where a = 5x, b = 2y]
=a3b3=(5x)3(2y)3=125x38y3

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