Find-i 1225 of a litreii 58 of a kilogramiii 35 of an hour

We have: (i) 1225 of 1 L = 1225 of 1000 ml = 1000 #215;1225 ml = (40 #215; 12) ml = 480 ml (ii)58 of 1 kg = 58 of 1000 g = 1000 #215;58 g = (125 #21 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Conversion of Units of Measurement

Find:i 1225 o...

Question

Find:

(i) $\frac{12}{25}$ of a litre
(ii) $\frac{5}{8}$ of a kilogram
(iii) $\frac{3}{5}$ of an hour

Open in App

Solution

We have:

(i) $\frac{12}{25}$ of 1 L = $\frac{12}{25}$ of 1000 ml = $(1000 \times \frac{12}{25})$ ml = (40 $\times$ 12) ml = 480 ml

(ii) $\frac{5}{8}$ of 1 kg = $\frac{5}{8}$ of 1000 g = $(1000 \times \frac{5}{8})$ g = (125 $\times$ 5) g = 625 g

(iii) $\frac{3}{5}$ of 1 h = $\frac{3}{5}$ of 60 min = $(60 \times \frac{3}{5})$ min = (12 $\times$ 3) min = 36 min

Suggest Corrections

Similar questions

Q. Evaluate:
(i)

\frac{- 3}{5} \times \frac{10}{7}

(ii)

{(\frac{- 5}{8})}^{- 1}

(iii)

{(- 6)}^{- 1}

Q. (i)

\frac{3}{4} and \frac{- 3}{5}

(ii)

- 3 and \frac{3}{5}

(iii)

\frac{- 7}{27} and \frac{11}{18}

(iv)

\frac{31}{- 4} and \frac{- 5}{8}

Q. Verify the following:
(i)

\frac{- 12}{5} + \frac{2}{7} = \frac{2}{7} + \frac{- 12}{5}

(ii)

\frac{- 5}{8} + \frac{- 9}{13} = \frac{- 9}{13} + \frac{- 5}{8}

(iii)

3 + \frac{- 7}{12} = \frac{- 7}{12} + 3

(iv)

\frac{2}{- 7} + \frac{12}{- 35} = \frac{12}{- 35} + \frac{2}{- 7}

Q. Find:

(i)

\frac{1}{3}

of 24
(ii)

\frac{3}{4}

of 32
(iii)

\frac{5}{9}

of 45
(iv)

\frac{7}{50}

of 1000
(v)

\frac{3}{20}

of 1020
(vi)

\frac{5}{11}

of Rs 220
(vii)

\frac{4}{9}

of 54 metres
(viii)

\frac{6}{7}

of 35 litres
(ix)

\frac{1}{6}

of an hour
(x)

\frac{5}{6}

of an year
(xi)

\frac{7}{20}

of a kg
(xii)

\frac{9}{20}

of a metre
(xiii)

\frac{7}{8}

of a day
(xiv)

\frac{3}{7}

of a week
(xv)

\frac{7}{50}

of a litre

Q. Find:
(i)

\frac{1}{2} of 4 \frac{2}{9}

(ii)

\frac{5}{8} of 9 \frac{2}{3}

(iii)

\frac{2}{3} of \frac{9}{16}

Join BYJU'S Learning Program

Find: (i) 1225 of a litre (ii) 58 of a kilogram (iii) 35 of an hour

We have: (i) 1225 of 1 L = 1225 of 1000 ml = 1000×1225 ml = (40 × 12) ml = 480 ml (ii)58 of 1 kg = 58 of 1000 g = 1000×58 g = (125 ×5) g = 625 g (iii) 35 of 1 h = 35 of 60 min = 60×35 min = (12 × 3) min = 36 min

Find:

(i) $\frac{12}{25}$ of a litre
(ii) $\frac{5}{8}$ of a kilogram
(iii) $\frac{3}{5}$ of an hour