Find:

(i) 4.8 ÷ 10 (ii) 52.5 ÷ 10 (iii) 0.7 ÷ 10

(iv) 33.1 ÷ 10 (v) 272.23 ÷ 10 (vi) 0.56 ÷ 10

(vii) 3.97 ÷ 10

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Solution

We know that when a decimal number is divided by a multiple of 10 only (i.e., 10, 100, 1000, etc.), the decimal point will be shifted to the left by as many places as there are zeroes. Since here we are dividing by 10, the decimal will shift to the left by 1 place.

(i) 4.8 ÷ 10 = 0 .48

(ii) 52.5 ÷ 10 = 5.25

(iii) 0.7 ÷ 10 = 0.07

(iv) 33.1 ÷ 10 = 3.31

(v) 272.23 ÷ 10 = 27.223

(vi) 0.56 ÷ 10 = 0.056

(vii) 3.97 ÷ 10 = 0.397

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Find:

(i) $1.3 \times 10$ (ii) $36.8 \times 10$ (iii) $153.7 \times 10$

(iv) $168.07 \times 10$ (v) $31.1 \times 100$ (vi) $156.1 \times 100$

(vii) $3.62 \times 100$ (viii) $43.07 \times 100$ (ix) $0.5 \times 10$

(x) $0.08 \times 10$ (xi) $0.9 \times 100$ (xii) $0.03 \times 1000$

Which of the following indicates the correct order of acidic strength of the following acids.

I. HCOOH (Ka = 1.8 $\times$ $10^{- 4}$ )

II. $C H_{3} C O O H$ (Ka = 1.8 $\times$ $10^{- 5}$ )

III : HCN (Ka = 4.8 $\times$ $10^{- 10}$ )

IV: HS- (Ka = 1 $\times$ 10-14)

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