Question

Find:
(i) $9^{\frac{3}{2}}$
(ii) ${32}^{\frac{2}{5}}$

Answer 1

(i) $9^{\frac{3}{2}}$

$=(3^2{)}^{\frac{3}{2}}$

$=\left(3^{2\times \frac{3}{2}}\right)$

$=3^3$

$=27$
(ii) ${32}^{\frac{2}{5}}$

$=(2^5{)}^{\frac{2}{5}}$

$=\left(2^{5\times \frac{2}{5}}\right)$

$=2^2$

$=4$