Find - i - 1 - x 2 -81 dx

∫1x^2+81 dx=∫d xx^2+9^2=19tan^ 1(x9)+C ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Integrating Factor

Find : i ∫ ...

Question

Find :
(i) $\int \frac{1}{x^{2} + 81} d x$

Open in App

Solution

Suggest Corrections

Similar questions

\int \frac{1}{x^{2} + 81} d x

\int \frac{x^{2} + 9}{x^{4} + 81} d x

\int \frac{x^{2} + 9}{x^{4} - 2 x^{2} + 81} d x

\int \frac{x^{2} + 9}{x^{4} - 2 x^{2} + 81} d x

x^{2} + \frac{1}{x^{2}} = 6

x^{3} - \frac{1}{x^{3}}

x^{6} + \frac{1}{x^{6}}

Join BYJU'S Learning Program

Related Videos

Methods of Solving First Order, First Degree Differential Equations

MATHEMATICS

Watch in App

Explore more

Join BYJU'S Learning Program