Question

Find image of point $(1,3,4)$ in the plane $2x-y+z+3=0$.

Answer 1

$2x-y+z+3=0$

$Thegivenpoints\left(1,3,4\right)\frac{x-1}{2}=\frac{y-3}{-1}=\frac{z-4}{1}=\frac{-2\left(2-3+4+3\right)}{6}\frac{x-1}{2}=\frac{y-3}{-1}=\frac{z-4}{1}=-2$

$Imageof\left(1,3,4\right)is:\left(-3,5,2\right)$