Question

Find in degree the angle subtended at the center of a circle of diameter 50 cm by an arc of length 11 cm.

Answer 1

Here,$r=25$ cm and $s=11$ cm. Therefore,

$\theta ={\left(\frac{s}{r}\right)}^R$ or $\theta ={\left(\frac{11}{25}\right)}^R={(\frac{11}{25}\times \frac{180}{\pi })}^{\circ }$

$={(\frac{11}{25}\times \frac{180}{22}\times 7)}^{\circ }$

$={\left(\frac{126}{5}\right)}^{\circ }{\left(25\frac{1}{5}\right)}^{\circ }={25}^{\circ }(\frac{1}{5}\times 60)={25}^{\circ }{12}^{\prime }$
Ans: 25