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Byju's Answer
Standard XII
Mathematics
Sign of Trigonometric Ratios in Different Quadrants
Find ∫x2+sin ...
Question
Find
∫
(
x
2
+
s
i
n
2
x
)
s
e
c
2
x
1
+
x
2
d
x
.
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Solution
Let
I
=
∫
(
x
2
+
s
i
n
2
x
)
s
e
c
2
x
1
+
x
2
d
x
.
=
∫
(
1
+
x
2
+
2
s
i
n
2
x
−
1
)
s
e
c
2
x
1
+
x
2
d
x
⇒
I
=
∫
(
1
+
x
2
−
c
o
s
2
x
)
s
e
c
2
x
1
+
x
2
d
x
=
∫
(
1
+
x
2
)
s
e
c
2
x
−
1
1
+
x
2
d
x
⇒
I
=
∫
[
s
e
c
2
x
−
1
1
+
x
2
]
d
x
=
t
a
n
x
−
t
a
n
−
1
x
+
C
.
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Q.
∫
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x
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