Find -1-1-x2ex-1-x dx on I where I- 0- - -

x+(1/x)=t #10;then (1 (1/x^2))dx=dt ∴ I=∫ e^t dt =e^t+c =e^x+(1/x)+c ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Integration by Substitution

Find ∫1-1/x...

Question

Find $\int (1 - \frac{1}{x^{2}}) e^{(x + \frac{1}{x})} d x$ on I where $I = (0, \infty) .$

Open in App

Solution

Suggest Corrections

Similar questions

\int (1 - \frac{1}{x^{2}}) e^{x + \frac{1}{x}} d x

\int (1 - \frac{1}{x^{2}}) e^{x + 1 / x} d x = e^{x + 1 / x} .

I = \int_{0}^{1} c o s (2 C o t^{- 1} \sqrt{\frac{1 - x}{1 + x}}) d x t h e n

I = \int {tan}^{- 1} (1 + \sqrt{x}) d x

I

I = \int \sqrt{\frac{1 - \sqrt{x}}{1 + \sqrt{x}}} d x,

Join BYJU'S Learning Program