Find iso-electric point of amino acid :

3.3

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5.9

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9.6

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11.8

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Solution

The correct option is A $3.3$
$C H_{3} - C H | N_{3} - C O O H$ $C O O H - P k_{a_{1}} = 2.2$
$N_{3}^{+} - P K_{a_{2}} = 4.4$
Calculation of amino acid $,$
$∙$ This step is refers to the image $.$
At low $p^{H}$ all protonated $.$
$P . I$ of amino acid $= \frac{1}{2} (p k_{a^{1}} + p k_{a^{2}})$
$= \frac{1}{2} (2.2 + 4.4) = \frac{1}{2} \times 6.6 = 3.3$

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Find iso-electric point of amino acid :

The correct option is A 3.3CH3−CH|N⊕H3−COOH COOH−Pka1=2.2 N+3−PKa2=4.4Calculation of amino acid,∙ This step is refers to the image.At low pH all protonated.P.I of amino acid=12(pka1+pka2) =12(2.2+4.4)=12×6.6=3.3