Find its period of revolution. (in s)

0.0517

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.0314

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.025

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.014

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $0.0314$
Angular speed $ω = \frac{v}{r} = \frac{20 m / s}{0.1 m} = 200 r a d / s . . . (1)$
Also, we know $ω = \frac{2 π}{p e r i o d o f o n e r e v o l u t i o n (s e c)} . . . (2)$
Putting the value from equation $(1)$ in $(2)$
$\Rightarrow ω = \frac{2 π}{p e r i o d o f o n e r e v o l u t i o n (s e c)} = 200 r a d / s$
$\Rightarrow$ Period of one revolution $= \frac{2 π}{200} = 0.0314 s e c$

Suggest Corrections

Similar questions

1.6 \times 10^{- 16} s .

s^{- 1}

60

{r a d s}^{- 1}

1.6 \times 10^{- 16} s .

s^{- 1}

Join BYJU'S Learning Program