Question

Find $k$ given the consecutive arithmetic terms:
$32,k,3$

Answer 1

Since, $32,k,3$ are in A.P

$\Rightarrow k-32=3-k$

$2k=3+32$

$2k=35$

$\therefore k=\frac{35}{2}$

when $k=\frac{35}{2}$ series is $32,\frac{35}{2},3$